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  • Question 1 - A study designed to examine the benefits of adding a new antiplatelet to...

    Incorrect

    • A study designed to examine the benefits of adding a new antiplatelet to aspirin after a myocardial infraction. The recorded results give us the percentage of patients that reported myocardial infraction within a three month period. The percentage was 4% and 3% for aspirin and the combination of drugs respectively.

      How many further patients needed to be treated in order for one patient to avoid any more heart attacks during 3 months?

      Your Answer: Cannot calculate without more data

      Correct Answer: 100

      Explanation:

      Number needed to treat can be defined as the number of patients who need to be treated to prevent one additional bad outcome.

      It can be found as:

      NNT=1/Absolute Risk Reduction (rounded to the next integer since number of patients can be integer only).

      where ARR= (Risk factor associated with the new drug group) — (Risk factor associated with the currently available drug)

      So,

      ARR= (0.04-0.03)

      ARR= 0.01

      NNT= 1/0.01

      NNT=100

    • This question is part of the following fields:

      • Statistical Methods
      36.3
      Seconds
  • Question 2 - A 49-year-old female has presented to her physician with complaints of a lump...

    Correct

    • A 49-year-old female has presented to her physician with complaints of a lump in her groin area. The lump is painless and is more prominent in coughing.
      On examination, the lump's location is inferior and lateral to the pubic tubercle. This points towards the diagnosis of femoral hernia, where part of her intestines has entered the femoral canal, causing a bulge in the femoral triangle. The femoral triangle is an anatomical region in the upper thigh.

      Name the structures found in the femoral triangle, laterally to medially.

      Your Answer: Femoral nerve, femoral artery, femoral vein, empty space, lymphatics

      Explanation:

      The femoral triangle is a wedge-shaped area found within the superomedial aspect of the anterior thigh. It is a passageway for structures to leave and enter the anterior thigh.

      Superior: Inguinal ligament
      Medial: Adductor longus
      Lateral: Sartorius
      Floor: Iliopsoas, adductor longus and pectineus

      The contents include: (medial to lateral)
      Femoral vein
      Femoral artery-pulse palpated at the mid inguinal point
      Femoral nerve
      Deep and superficial inguinal lymph nodes
      Lateral cutaneous nerve
      Great saphenous vein
      Femoral branch of the genitofemoral nerve

    • This question is part of the following fields:

      • Anatomy
      40.1
      Seconds
  • Question 3 - A laser is a device that stimulates atoms or molecules to emit light...

    Correct

    • A laser is a device that stimulates atoms or molecules to emit light at particular wavelengths and amplifies that light, typically producing a very narrow beam of radiation. This can be of visible, infrared, or ultraviolet wavelengths. They have been widely utilized in theatre environment.

      Which of the following safety measures is most likely to reduce chances of eye injury to the theatre personnel?

      Your Answer: Wearing laser protective goggles

      Explanation:

      Eye damage is the most common potential hazard associated with laser energy. Everyone in the laser treatment room has the risk of eye exposure when working with a Class 3b or Class 4 healthcare laser system, and damage to various structures in the eye depending on wavelength of the laser if they are unprotected.

      Red and near-infrared light (400-1400 nm) has very high penetration power. The light causes painless burns on the retina after it is absorbed by melanin in the pigment epithelium just behind the photoreceptors.

      Infrared radiation (IR), or infrared light (>1060 nm), is a type of radiant energy that’s invisible to human eyes and hence won’t elicit the protective blink.

      Ultraviolet light (<400 nm) is also a form of electromagnetic radiation which is can penetrate the cornea and be absorbed by the iris or the pupil and cause burn injuries or cataract occur due to irreversible photochemical retinal damage. Safety eyewear is the best method of providing eye protection and are designed to absorb light specific to the laser being used. Laser protective eyewear (LPE) includes glasses or goggles of proper optical density (OD). The lenses should not be glass or plastic. The LPE should withstand direct and diffuse scattered laser beams. The laser protection supervisor (LPS) or LSO is an individual who is responsible for any clinical area in which lasers are used. They are expected to have a certain level of equipment and determine what control measures are appropriate, for each individual system, but their presence does not guarantee the chances of having an eye injury. Class 1 lasers are generally safe under every conceivable condition and is not likely to cause any eye damage. Class 3b or Class 4 medical laser systems are utilized in healthcare which have their own safety precautions. Polarized spectacles can make your eyes more comfortable by eliminated glare, however, they will not be able to offer any protection against wavelengths at which laser act.
      Using short bursts to reduce energy is also not correct as it would still be harmful to eye.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
      18.8
      Seconds
  • Question 4 - One of two divisions of the autonomic nervous system is the sympathetic nervous...

    Incorrect

    • One of two divisions of the autonomic nervous system is the sympathetic nervous system. It is both anatomically and physiologically different from the parasympathetic nervous system.

      Which best describes the anatomical layout of the sympathetic nervous system?

      Your Answer: Short myelinated preganglionic neurones from T1-L5 in lateral horns of white matter of spinal cord, synapse in sympathetic ganglia (neurotransmitter - acetyl choline), long unmyelinated postganglionic neurones, synapse with effector organ (neurotransmitter - adrenaline or noradrenaline)

      Correct Answer: Short myelinated preganglionic neurones from T1-L5 in lateral horns of grey matter of spinal cord, synapse in sympathetic ganglia (neurotransmitter - acetyl choline), long unmyelinated postganglionic neurones, synapse with effector organ (neurotransmitter - adrenaline or noradrenaline)

      Explanation:

      The autonomic nervous system is divided into the sympathetic and parasympathetic nervous system. They are anatomically and physiologically different.

      The sympathetic nervous system arises from the thoracolumbar outflow (T1-L5 ) at the lateral horns of grey matter of the spinal cord. Their preganglionic neurones are usually short myelinated and synapse in ganglia lateral to the vertebral column and have acetyl choline (Ach) as the neurotransmitter. Their postganglionic neurones are longer and unmyelinated and synapse with effector organ where the neurotransmitter is either adrenaline or noradrenaline.

      The outflow of the parasympathetic nervous system is craniosacral. The cranial part originates from the midbrain and medulla (cranial nerves III, VII, IX and X) and the sacral outflow is from S2, S3 and S4. Their preganglionic neurones are usually long myelinated and synapse in ganglia close to the target organ and has Ach as its neurotransmitter. The unmyelinated postganglionic neurones is shorter and they synapse with effector organ. The neurotransmitter here is also Ach.

      Both sympathetic and parasympathetic preganglionic neurons are cholinergic. Only the postganglionic parasympathetic neurons are cholinergic.

    • This question is part of the following fields:

      • Anatomy
      35.7
      Seconds
  • Question 5 - During a critical liver resection surgery, a 65-year-old man suffers uncontrolled hepatic bleeding....

    Incorrect

    • During a critical liver resection surgery, a 65-year-old man suffers uncontrolled hepatic bleeding. The 'Pringle manoeuvre is performed to stop the bleeding where the hepatic artery, portal vein, and common bile duct are clamped. These structures form the anterior boundary of the epiploic foramen.

      Which of the following vessels also contributes to the boundary of this region?

      Your Answer: Common hepatic artery

      Correct Answer: Inferior vena cava

      Explanation:

      The epiploic foramen (foramen of Winslow or aditus to the lesser sac) is found behind the free right border of the lesser omentum. A short, 3 cm slit serves as the entrance to the lesser sac from the greater sac.

      The epiploic foramen has the following boundaries:
      Anteriorly: hepatoduodenal ligament, the bile duct (anteriorly on the right), the hepatic artery (anteriorly on the left), and the portal vein (posteriorly) together with nerves and lymphatics
      Superiorly: the peritoneum of the posterior layer of the hepatoduodenal ligament runs over the caudate process of the liver
      Posteriorly: inferior vena cava
      Floor: upper border of the first part of the duodenum
      The anterior and posterior walls of the foramen are normally
      apposed, which partly explains why patients can develop large fluid
      collections isolated to the greater or lesser sac

      Rapid control of the hepatic artery and portal vein can be obtained by compression of the free edge of the lesser omentum (a ‘Pringle’ manoeuvre), which is a potentially useful technique in liver trauma and surgery.

    • This question is part of the following fields:

      • Anatomy
      15.8
      Seconds
  • Question 6 - In North America, there have been reports of paediatric patients dying after undergoing...

    Incorrect

    • In North America, there have been reports of paediatric patients dying after undergoing adenotonsillectomy for obstructive sleep apnoea.

      Respiratory depression/obstruction is thought to be the cause of death. The codeine dose was 0.5-1 mg/kg, given every 4-6 hours.

      In this group of patients, which of the following is the most likely cause of respiratory depression and obstruction?

      Your Answer: Accumulation of serum morphine-3-glucuronide

      Correct Answer: Exaggerated metabolism of codeine

      Explanation:

      Codeine is easily absorbed from the gastrointestinal tract and converted to morphine and norcodeine in the liver via O- and N-demethylation. Morphine and norcodeine are excreted almost entirely by the kidney, primarily as conjugates with glucuronic acid.

      By glucuronidation, phase II metabolism enzyme UDP-glucuronosyl transferase-2B7 converts morphine to morphine-3-glucuronide (M3G) and morphine-6-glucuronide (M6G) (UGT2B7).

      Approximately 60% of morphine is converted to M3G, with the remaining 6-10% converted to M6G. M3G is inactive, but M6G is said to be 4 to 650 times more potent on the MOP receptor than morphine.

      When codeine is consumed, cytochrome P450 2D6 in the liver converts it to morphine (CYP2D6).

      Some people have DNA variations that increase the activity of this enzyme, causing codeine to be converted to morphine more quickly and completely than in others. After taking codeine, these ultra-rapid metabolisers are more likely to have higher than normal levels of morphine in their blood.

      Respiratory depression/obstruction can be caused by high levels of morphine and M6G, especially in people who have a history of obstructive sleep apnoea. The estimated number of ultra-rapid metabolisers ranges from 1 to 7 per 100 people, but some ethnic groups may have as many as 28 per 100 people.

    • This question is part of the following fields:

      • Pathophysiology
      21.6
      Seconds
  • Question 7 - In reference to confounding variables, which among the given is not true? ...

    Incorrect

    • In reference to confounding variables, which among the given is not true?

      Your Answer: Age and sex are common confounders

      Correct Answer: In the analytic stage of a study confounding can be controlled for by randomisation

      Explanation:

      Randomisation can be used to provide control over the confounding variables during the design stage of a study however during analytical stage a technique called stratification is used for controlling confounding variables. Since the question asks for the information that is factually incorrect.

    • This question is part of the following fields:

      • Statistical Methods
      15.5
      Seconds
  • Question 8 - A 33-year-old woman known to be hypothyroid and taking 150 mcg l-thyroxine daily...

    Incorrect

    • A 33-year-old woman known to be hypothyroid and taking 150 mcg l-thyroxine daily is reviewed in the preoperative assessment clinic prior to a laparoscopic cholecystectomy.

      She has required three increases in her thyroid replacement therapy in the last six months.

      Her thyroid function tests are as follows:

      TSH 11 (normal range 0.4-4mU/L)
      T3 20 (normal range 9-25mU/L)
      T4 6.2 (normal range 3.5-7.8mU/L)

      What will explain this biochemical picture?

      Your Answer: Tissue level unresponsiveness to thyroid hormone

      Correct Answer: Poor compliance with medication

      Explanation:

      In patients with an intact hypothalamic-pituitary axis, serial TSH measurements are used to determine the adequacy of treatment with thyroid hormones . changes in TSH levels becoming apparent after approximately eight weeks of therapy with thyroid hormone replacement. Change in T3/T4 levels are seen before changes in TSH .

      In patients taking thyroid replacement therapy, the most frequent reason for persistent elevation of serum TSH is poor compliance. Patients who do not regularly take their L-thyroxine try and catch up just before a visit to a clinician for blood test.

      Tissue-level unresponsiveness to thyroid hormone is caused by mutation in the gene controlling a receptor for T3 and is rare.

      Reduced responsiveness of target tissues to thyroid hormone aka resistance to thyroid hormones (rTH) occurs when there is a mutation in the thyroid hormone receptor ? gene. It is a rare autosomal dominant inherited syndrome of reduced end-organ responsiveness to thyroid hormone and has two types:

      Generalised resistance (GrTH)
      Pituitary resistance (PrTH)

      Patients with rTH have normal or slightly elevated serum thyroid stimulating hormone (TSH) level, elevated serum free thyroxine (FT4) and free triiodothyronine (FT3) concentrations.

      Drugs that increase metabolism of thyroxine include:

      Warfarin
      Rifampin
      Phenytoin
      Phenobarbital
      St John’s Wort
      Carbamazepine

      These drugs lower circulating thyroid hormones and would be associated with a raised TSH but low T3/T4.

    • This question is part of the following fields:

      • Pathophysiology
      62.8
      Seconds
  • Question 9 - Of the following, which of these oxygen carrying molecules causes the greatest shift...

    Incorrect

    • Of the following, which of these oxygen carrying molecules causes the greatest shift of the oxygen-dissociation curve to the left?

      Your Answer: Haemoglobin (HbAA)

      Correct Answer: Myoglobin (Mb)

      Explanation:

      Myoglobin is a haemoglobin-like, iron-containing pigment that is found in muscle fibres. It has a high affinity for oxygen and it consists of a single alpha polypeptide chain. It binds only one oxygen molecule, unlike haemoglobin, which binds 4 oxygen molecules.

      The myoglobin ODC is a rectangular hyperbola. There is a very low P50 0.37 kPa (2.75 mmHg). This means that it needs a lower P50 to facilitate oxygen offloading from haemoglobin. It is low enough to be able to offload oxygen onto myoglobin where it is stored. Myoglobin releases its oxygen at the very low PO2 values found inside the mitochondria.

      P50 is defined as the affinity of haemoglobin for oxygen: It is the PO2 at which the haemoglobin becomes 50% saturated with oxygen. Normally, the P50 of adult haemoglobin is 3.47 kPa(26 mmHg).

      Foetal haemoglobin has 2 ? and 2 ?chains. The ODC is left shifted – this means that P50 lies between 2.34-2.67 kPa [18-20 mmHg]) compared with the adult curve and it has a higher affinity for oxygen. Foetal haemoglobin has no ? chains so this means that there is less binding of 2.3 diphosphoglycerate (2,3 DPG).

      Carbon monoxide binds to haemoglobin with an affinity more than 200-fold higher than that of oxygen. This therefore decreases the amount of haemoglobin that is available for oxygen transport. Carbon monoxide binding also increases the affinity of haemoglobin for oxygen, which shifts the oxygen-haemoglobin dissociation curve to the left and thus impedes oxygen unloading in the tissues.

      In sickle cell disease, (HbSS) has a P50 of 4.53 kPa(34 mmHg).

    • This question is part of the following fields:

      • Physiology
      16.8
      Seconds
  • Question 10 - Over the course of 10 minutes, a normally fit and well 22-year-old male...

    Correct

    • Over the course of 10 minutes, a normally fit and well 22-year-old male receives a 1 litre intravenous bolus of 20% albumin.

      Which of the following primary physiological responses in this patient has the highest chance to influence a change in urine output?

      Your Answer: Stimulation of atrial natriuretic peptide (ANP) secretion

      Explanation:

      The renal effects of atrial natriuretic peptide (ANP) secretion are as follows:

      Increased glomerular filtration rate by dilating the afferent glomerular arteriole. Moreover, it constricts the efferent glomerular arteriole, and relaxes the mesangial cells.
      Reduces sodium reabsorption in the collecting ducts and distal convoluted tubule.
      The renin-angiotensin system (RAS) is inhibited.
      Blood flow in the vasa recta is increased.

      Because plasma osmolality is unlikely to change, hypothalamic osmoreceptors are unaffected.

      The plasma protein has a molecular weight of 66 kDa, is not normally filtered into the proximal convoluted tubule, and has no osmotic diuretic effect.

      The following are some basic assumptions:

      Extracellular fluid (ECF) makes up one-third of total body water (TBW), while intracellular fluid makes up the other two-thirds (ICF)
      One-quarter plasma and three-quarters interstitial fluid make up ECF (ISF)
      The volume receptors in the atria have a 7-10% blood volume change threshold.
      The osmoreceptors are sensitive to changes in osmolality of 1-2 percent.
      The normal plasma osmolality before the transfusion is 287-290 mOsm/kg.
      The plasma protein solution is a colloid that is only delivered to the intravascular compartment. The tonicity remains unchanged.
      The blood volume increases by 20%, from 5,000 mls to 6,000 mls. This is higher than the volume receptor threshold of 7 to 10%.

    • This question is part of the following fields:

      • Pathophysiology
      35.7
      Seconds
  • Question 11 - Which of the following can be measured directly using spirometry? ...

    Incorrect

    • Which of the following can be measured directly using spirometry?

      Your Answer: Residual volume

      Correct Answer: Vital capacity

      Explanation:

      Spirometry measures the total volume of air that can be forced out in one maximum breath, that is the total lung capacity (TLC), to maximal expiration, that is the residual volume (RV).

      It is conducted using a spirometer which is capable of measuring lung volumes using techniques of dilution.

      During spirometry, the following measurements can be determined:
      Forced vital capacity (FVC)/vital capacity (VC): The maximum volume of air exhaled in one single forced breathe.
      Forced expiratory volume in one second (FEV1)
      FEV1/FVC ratio
      Peak expiratory flow (PEF): the maximum amount of air flow exhaled in one blow.
      Forced expiratory flow (mid expiratory flow): the flow at 25%, 50% and 75% of FVC
      Inspiratory vital capacity (IVC): The maximum volume of air inhaled after a full total expiration.

      Anatomical dead space is measured using a single breath nitrogen washout called the Fowler’s method.

      Residual volume and total lung capacity are both measured using the body plethysmograph or helium dilution

      The functional residual capacity is usually measured using a nitrogen washout or the helium dilution technique.

    • This question is part of the following fields:

      • Clinical Measurement
      9.9
      Seconds
  • Question 12 - A graph was plotted after administration of fentanyl infusion to a patient. The...

    Incorrect

    • A graph was plotted after administration of fentanyl infusion to a patient. The following are the x- and y-axis of the graph:

      X-axis: Dose of fentanyl
      Y-axis: Mu receptor occupancy, measured using positron emission tomography

      Given the data above, what would be the best representation of the graph if the data on the x-axis are converted to logarithms?

      Your Answer: Straight line to exponential curve

      Correct Answer: Rectangular hyperbola to sigmoid curve

      Explanation:

      The dose-response curve plots the graph of the dose (drug concentration) versus the response. As doses increase, the response increment diminishes; finally, doses may be reached at which no further increase in response can be achieved. This relation between drug concentration and effect is traditionally described by a hyperbolic curve. When the x-axis is plotted in log scale, the graph yields a sigmoid curve.

      Efficacy (Emax) and potency (EC50) can be derived from this curve. Emax is the maximal effect achievable, with increasing concentration of a drug. EC50 is the concentration of the drug, wherein half of the maximal effect is achieved.

      When the graph is plotted using a log [response/1-response] against log dose, the sigmoid curve becomes a straight line (Hill plot). A graph that transforms from a straight line to exponential curve is mathematically incorrect. A graph that transforms from either a wash-in or wash-out exponential curve to a straight line comes from an initial set of data plotted against time, to a logarithmic transformation of the initial data set against time.

    • This question is part of the following fields:

      • Statistical Methods
      20.5
      Seconds
  • Question 13 - Which of the following statements about the central venous pressure (CVP) waveform is...

    Incorrect

    • Which of the following statements about the central venous pressure (CVP) waveform is true?

      Your Answer: The C wave represents atrial contraction

      Correct Answer: Third degree heart block causes canon A waves

      Explanation:

      The central venous pressure (CVP) waveform depicts changes of pressure within the right atrium. Different parts of the waveform are:

      A wave: which represents atrial contraction. It is synonymous with the P wave seen during an ECG. It is often eliminated in the presence of atrial fibrillation, and increased tricuspid stenosis, pulmonary stenosis and pulmonary hypertension.

      C wave: which represents right ventricle contraction at the point where the tricuspid valve bulges into the right atrium. It is synonymous with the QRS complex seen on ECG.

      X descent: which represents relaxation of the atrial diastole and a decrease in atrial pressure, due to the downward movement of the right ventricle as it contracts. It is synonymous with the point before the T wave on ECG.

      V wave: which represents an increase in atrial pressure just before the opening of the tricuspid valve. It is synonymous with the point after the T wave on ECG. It is increased in the background of a tricuspid regurgitation.

      Y descent: which represents the emptying of the atrium as the tricuspid valve opens to allow for blood flow into the ventricle in early diastole.

      Canon waves: which refer to large waves present on the trace that do not correspond to the A, V or C waves. They usually occur in a background of complete heart blocks or junctional arrythmias.

    • This question is part of the following fields:

      • Clinical Measurement
      17.9
      Seconds
  • Question 14 - What is the mechanism of the pupillary reflex arc? ...

    Incorrect

    • What is the mechanism of the pupillary reflex arc?

      Your Answer: Oculomotor nerve fibres to the pretectal nucleus

      Correct Answer: Oculomotor nerve fibres from the Edinger-Westphal nuclei

      Explanation:

      Pupil size is reduced by the pupillary light reflex and during accommodation for near vision. In the pupillary light reflex, light that strikes the retina is processed by retinal circuits that excite W-type retinal ganglion cells. These cells respond to diffuse illumination. The axons of some of the W-type cells project through the optic nerve and tract to the pretectal area, where they synapse in the olivary pretectal nucleus. This nucleus contains neurons that also respond to diffuse illumination. Activity of neurons of the olivary pretectal nucleus causes pupillary constriction by means of bilateral connections with parasympathetic preganglionic neurons in the Edinger-Westphal nuclei. The reflex results in contraction of the pupillary sphincter muscles in both eyes, even when light is shone into only one eye.

    • This question is part of the following fields:

      • Pathophysiology
      84.7
      Seconds
  • Question 15 - Among the following which one is not a criterion for the assessment of...

    Incorrect

    • Among the following which one is not a criterion for the assessment of causality?

      Your Answer: Consistency

      Correct Answer: Sensitivity

      Explanation:

      For establishing a cause effect relationship, following criteria must be met:

      1. Coherence & Consistency

      2. Temporal Precedence

      3. Specificity

      As can be seen, sensitivity (The probability of a positive test) is not among these deciding factors..

    • This question is part of the following fields:

      • Statistical Methods
      10.2
      Seconds
  • Question 16 - Which one of the following patients presenting for elective surgery has an American...

    Incorrect

    • Which one of the following patients presenting for elective surgery has an American Society of Anaesthesiologists (ASA) preoperative physical status grading of III?

      Your Answer: A 65-year old woman with a BMI of 34 with treated hypertension with no functional limitations

      Correct Answer: A 50-year old man with a BMI of 41 with a reduced exercise tolerance

      Explanation:

      The ASA physical status classification system is a system for assessing the fitness of patients before surgery. It was last updated in October 2014.

      ASA I A normal healthy patient
      ASA II A patient with mild systemic disease
      ASA III A patient with severe systemic disease
      ASA IV A patient with severe systemic disease that is a constant threat to life
      ASA V A moribund patient who is not expected to survive without the operation
      ASA VI A declared brain-dead patient whose organs are being removed for donor purposes

      A 20-year old woman who is 39-weeks pregnant with no other medical conditions – ASA II

      A 35-year-old man with a BMI of 29 with a good exercise tolerance who smokes-ASA II

      A 50-year old man with a BMI of 41 with a reduced exercise tolerance -ASA III

      A 65-year old woman with a BMI of 34 with treated hypertension with no functional limitations-ASA II

      A 73-year old man who has had a TIA ten-weeks ago but has a good exercise tolerance and is a non-smoker-ASA IV

    • This question is part of the following fields:

      • Clinical Measurement
      24
      Seconds
  • Question 17 - A 67-year-old man, presents with an embolus in the lower limbs. He has...

    Incorrect

    • A 67-year-old man, presents with an embolus in the lower limbs. He has previous medical history of atrial fibrillation. After examination and diagnostic investigations, he is scheduled for a transpopliteal embolectomy, which will require the surgeons to explore the central region of the popliteal fossa.

      What structures will the surgeons come across after incising the deep fascia?

      Your Answer: Popliteal artery

      Correct Answer: Tibial nerve

      Explanation:

      The tibial nerve lies on top of the vessels contained within the inferior aspect of the popliteal fossa.

      In the superior aspect of the fossa, the tibial nerve runs lateral to the vessels, before then travelling superficial to the vessels, and then finally changing course to lie medial to the vessels.

      The popliteal artery is the most deep structure present in the popliteal fossa

    • This question is part of the following fields:

      • Anatomy
      14.1
      Seconds
  • Question 18 - A 76-year-old female, presents to her GP. She complains of fatigue and increased...

    Correct

    • A 76-year-old female, presents to her GP. She complains of fatigue and increased shortness of breath. On examination, she is noted to have pallor, an increased respiratory and heart rate. Her GP requests further diagnostic investigations, including a full blood count (FBC) which finds decreased MCV and MCHC.

      What is the most likely cause of her symptoms?

      Your Answer: Iron deficiency

      Explanation:

      The patient’s diagnosis is microcytic hypochromic anaemia which is often as a result of iron deficiency and thalassaemia.

      Macrocytic anaemia is often caused by folate and B12 deficiencies and alcohol abuse.

      Normocytic normochromic anaemia is often caused by acute blood loss, haemolytic anaemia, anaemia of chronic disease and leucoerythroblastic anaemias.

    • This question is part of the following fields:

      • Clinical Measurement
      18.9
      Seconds
  • Question 19 - Which structure has the greatest amount of musculi pectinati? ...

    Incorrect

    • Which structure has the greatest amount of musculi pectinati?

      Your Answer: Aortic valve

      Correct Answer: Right atrium

      Explanation:

      The pectinate muscles (musculi pectinati) are parallel muscular ridges that extend anterolaterally on the right atrial walls. The most prominent pectinate muscle, which forms the bridge of the sulcus terminalis internally, is the taenia sagittalis (second crest or septum spurium).

      In the left atrium, the pectinate muscles are confined to the inner surface of its atrial appendage. They tend to be fewer and smaller than in the right atrium. This is due to the embryological origin of the auricles, which are the true atria.

      Pectinate muscles of the atria are different from the trabeculae carneae, which are found on the inner walls of both ventricles.

      The interior of the right atrium has five distinct features:
      1. Sinus venarum – smooth, thin-walled posterior part of the right atrium where the SVC, IVC, and coronary sinus open
      2. Musculi pectinati – a rough anterior wall of pectinate muscles
      3. Tricuspid valve orifice – the opening through which the right atrium empties blood into the right ventricle
      4. Crista terminalis – separates the rough (musculi pectinati) from the smooth (sinus venarum) internally
      5. Fossa ovalis – a thumbprint size depression in the interatrial septum, which is a remnant of the oval foramen and its valve in the foetus

    • This question is part of the following fields:

      • Anatomy
      4.9
      Seconds
  • Question 20 - The child-Pugh scoring system can be used, if risk classifying a patient with...

    Incorrect

    • The child-Pugh scoring system can be used, if risk classifying a patient with chronic liver disorder earlier to anaesthesia.

      Which one is the best combination of clinical signs and examinations used within the Child-Pugh scoring system?

      Your Answer: Ascites, grade of encephalopathy, albumin, glucose and INR

      Correct Answer: Ascites, grade of encephalopathy, albumin, bilirubin and INR

      Explanation:

      In the Child-Pugh classification system, the following 5 components are determined or calculated in order:

      Ascites

      Grade of encephalopathy

      Serum bilirubin (?mol/L)

      Serum Albumin (g/L)

      Prothrombin time or INR

      Raised liver enzymes are not the component of the classification system.

    • This question is part of the following fields:

      • Basic Physics
      25.3
      Seconds
  • Question 21 - Fixed performance devices like high air flow oxygen enrichment (HAFOE) masks have large...

    Incorrect

    • Fixed performance devices like high air flow oxygen enrichment (HAFOE) masks have large volumes of air entrained into a flow of 100% oxygen.

      The term that best describes the physics behind air entrainment is?

      Your Answer: Venturi effect

      Correct Answer: Bernoulli's principle

      Explanation:

      Bernoulli’s principle states that as the speed of a moving fluid increases, there is a simultaneously decrease in static pressure or a decrease in the fluid’s potential energy.
      This is seen in the simultaneous increase in speed and kinetic energy and fall in pressure that causes entrainment of large volumes of air into a flow of 100% oxygen in the nozzle of HAFOE masks.

      The reduction in fluid pressure that happens when a fluid flows through a constriction in a tube is the Venturi effect.

      When a flow of gas or liquid attaches itself to a nearby surface and remains attached even when the surface curves away from the initial direction of flow, this is the Coanda effect.

      The branch of engineering and technology that is concerned with the building of devices that use the flow and pressure of a fluid for functions usually performed by electronic devices is Fluidics . Fluidic logic is used to power some ventilators.

      The branch of engineering that utilises pressurised gases is Pneumatics.

    • This question is part of the following fields:

      • Basic Physics
      12.8
      Seconds
  • Question 22 - From the following statements, which is true of humidification? ...

    Incorrect

    • From the following statements, which is true of humidification?

      Your Answer: The wet and dry bulb hygrometer measures absolute humidity

      Correct Answer: Ultrasonic humidifier can achieve greater than 100% relative humidity

      Explanation:

      Increasing temperature increases the amount of water vapour contained in air; for example, at 20°C, air contains about 17 g/m3, and at 37°C, air contains about 44 g/m3. The wet and dry bulb hygrometer, like the hair hygrometer, measures relative humidity.

      Under normal operating conditions, Heat and moisture exchangers (HMEs) allows relative humidity of up to 70% to be achieved. Mucus can impair their performance, and they should not be used for longer than 24 hours.

      Hot water bath humidifiers might cause scalding, condensed water in the tubing can interfere with gas flow, and there is a danger of infection.

      The ultrasonic humidifier operates at roughly 2 MHz and may attain relative humidity levels much above 100%.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
      16.3
      Seconds
  • Question 23 - Out of the following, which artery is NOT a branch of the hepatic...

    Incorrect

    • Out of the following, which artery is NOT a branch of the hepatic artery?

      Your Answer: Right hepatic artery

      Correct Answer: Pancreatic artery

      Explanation:

      The common hepatic artery arises from the celiac artery and has the following branches:
      1. hepatic artery proper that branches into –
      a. cystic artery to supply the gallbladder
      b. left and right hepatic arteries to supply the liver
      2. gastroduodenal artery that branches into
      a. right gastroepiploic artery
      b. superior pancreaticoduodenal artery
      3. right gastric artery

      The pancreatic artery is a branch of the splenic artery.

    • This question is part of the following fields:

      • Anatomy
      8.4
      Seconds
  • Question 24 - A 27-year-old woman presents to emergency department. She is experiencing generalised seizures.

    She is...

    Incorrect

    • A 27-year-old woman presents to emergency department. She is experiencing generalised seizures.

      She is given emergency management of her symptoms before being referred to the neurologist who diagnoses her with new onset of tonic-clonic epilepsy.

      What is the most appropriate first line of treatment?

      Your Answer: Sodium valproate should be offered as a first line of treatment

      Correct Answer: Lamotrigine should be offered as first line of treatment

      Explanation:

      Tonic-clonic (Grand mal) epilepsy is characterised by a general loss of consciousness with violent involuntary muscle contractions.

      The NICE guidelines for treatment indicates the use of sodium valproate and lamotrigine, but sodium valproate unsuitable in this case and she is a woman of reproductive age and it is known to have teratogenic effects. Lamotrigine is a more suitable choice, prescribed as 800mg daily.

      NICE guidelines also advice an additional prescription of 5mg of folic acid daily for women on anticonvulsant therapy looking to get pregnant. It also warns of the need for extra contraceptive precaution as there is a possibly that the anticonvulsant agent can reduce levels of contraceptive agents.

      Stimulation of the vagal nerve stimulation is only necessary in patients who are refractory to medical treatment and not candidates for surgical resection.

    • This question is part of the following fields:

      • Pathophysiology
      30.3
      Seconds
  • Question 25 - A 78-year-old man with a previous history of ischaemic heart disease is admitted...

    Incorrect

    • A 78-year-old man with a previous history of ischaemic heart disease is admitted to hospital. He is scheduled for a cardiopulmonary exercise test (CPX) before he undergoes an elective abdominal aneurysm repair.

      What measurement obtained during a CPX test alone provides the best indication for postoperative mortality?

      Your Answer: VO2 peak

      Correct Answer: Anaerobic threshold

      Explanation:

      Cardiopulmonary exercise testing (CPX, CPEX, CPET) is a non-invasive testing method used to determine the performance of the heart, lungs and skeletal muscle. It measures the exercise tolerance of the patient.

      The parameters measured include:

      ECG and ST-segment analysis and blood pressure
      Oxygen consumption (VO2)
      Carbon dioxide production (VCO2)
      Gas flows and volumes
      Respiratory exchange ratio (RER)
      Respiratory rate
      Anaerobic threshold (AT)

      The anaerobic threshold (AT) is an estimate of exercise ability. Any measurement below 11 ml/kg/min is usually related with an increase in mortality, especially when there is a background of myocardial ischaemia occurring during the test.

      Peak VO2 <20 mL/kg with a low AT have a correlation with postoperative complications and a 30 day mortality. The CPX test is used for risk-testing patients prior to surgery to determine the appropriate postoperative care facilities. The V slope measured in CPX testing represents VO2 versus VCO2 relationship. During AT, the ramp of V slope increases, but does not provide a picture of postoperative mortality.

    • This question is part of the following fields:

      • Clinical Measurement
      18.7
      Seconds
  • Question 26 - A new intravenous neuromuscular blocking agent has been developed. It has a hepatic...

    Incorrect

    • A new intravenous neuromuscular blocking agent has been developed. It has a hepatic extraction ratio of 0.25 and three quaternary nitrogen atoms in its structure. It has been discovered that it has a half-life of fifteen minutes in healthy volunteers.

      Which of the following elimination mechanisms is the most likely to explain this pharmacological behaviour?

      Your Answer: It is an ester metabolised in the plasma and tissues

      Correct Answer: It is filtered and not reabsorbed by the renal tubules

      Explanation:

      The neuromuscular blocking agent is likely to be filtered and not reabsorbed by the renal tubules due to an exclusion process.

      Neuromuscular blocking agents that contain one or more quaternary nitrogen atoms are polar and ionised. As a result, the molecules have low lipid solubility, low membrane diffusion capacity, and low distribution volume.

      It’s unlikely that a compound with three quaternary nitrogen atoms is an ester. Its high polarity would prevent molecules from moving quickly into tissues.

      When drugs have a low hepatic extraction ratio (0.3), the venous and arterial drug concentrations are nearly identical. The liver is not the primary site of drug metabolism.

      Therefore:

      Changes in liver blood flow have no effect on clearance.
      Protein binding, intrinsic metabolism, and excretion are all very sensitive to changes in clearance.
      When taken orally, there is no first-pass metabolism.

      There is no reason for the lungs to eliminate any neuromuscular blocking agent.

    • This question is part of the following fields:

      • Pharmacology
      26.7
      Seconds
  • Question 27 - A survey aimed at finding out mean glucose level in individuals that took...

    Incorrect

    • A survey aimed at finding out mean glucose level in individuals that took antipsychotics medicines was conducted. The results were as follows:

      Mean Value: 7mmol/L

      Standard Deviation: 6mmol/L

      Sample Size: 9

      Standard Error: 2mmol/L

      For a confidence interval of 95%, which of the option presents the correct range up to the nearest value?

      Your Answer: 5-9 mmol/L

      Correct Answer: 3-11 mmol/L

      Explanation:

      Key Point: While finding out confidence intervals, standard errors are used. Standard error and Standard deviation are two distinct entities and should not be confused.

      For 99.7% confidence interval, you can find the range as follows:

      Multiply the standard error by 3.

      Subtract the answer from mean value to get the lower limit.

      Add the answer obtained in step 1 from the mean value to get the upper limit.

      The range turns out to be 1-13 mmol/L.

      For a confidence interval of 68%, multiply the standard error with 1 and repeat the process. The range found for this interval is 3-11 mmol/L.

      For a 95% confidence interval. Standard Error is multiplied by 1.96 which gives us the limit ranging from 3.08 to 10.92 mmol/L which could be approximated to 3-11 mmol/L.

    • This question is part of the following fields:

      • Statistical Methods
      20.8
      Seconds
  • Question 28 - A 64-year old male has shortness of breath on exertion and presented to...

    Correct

    • A 64-year old male has shortness of breath on exertion and presented to the cardiology clinic. He has a transthoracic echo performed to help in assessing the function of his heart.
      How can this echo aid in calculating cardiac output?

      Your Answer: (end diastolic LV volume - end systolic LV volume) x heart rate

      Explanation:

      Cardiac output = stroke volume x heart rate

      Left ventricular ejection fraction = (stroke volume / end diastolic LV volume ) x 100%

      Stroke volume = end diastolic LV volume – end systolic LV volume

      Pulse pressure = Systolic Pressure – Diastolic Pressure

      Systemic vascular resistance = mean arterial pressure / cardiac output
      Factors that increase pulse pressure include:
      -a less compliant aorta (this tends to occur with advancing age)
      -increased stroke volume

    • This question is part of the following fields:

      • Physiology And Biochemistry
      23.6
      Seconds
  • Question 29 - A log-dose response curve is plotted after drug A is given. The shape...

    Incorrect

    • A log-dose response curve is plotted after drug A is given. The shape of this curve is sigmoid, with a maximum response of 100%.

      The log-dose response curve of drug A shifts to the right with a maximum response of 100 percent when drug B is administered.

      What does this mean in terms of drug B?

      Your Answer: Drug B has affinity for the receptor but induces different pharmacological effects

      Correct Answer: Drug B has affinity for the receptor but has no intrinsic efficacy

      Explanation:

      Drug A is a pure agonist for the receptor, with high intrinsic efficacy and affinity, according to the log-dose response curve.

      Drug B, on the other hand, works as a competitive antagonist. It binds to the receptor but has no inherent efficacy. Drug A’s efficacy will not change, but its potency will be reduced.

      A partial agonist is a drug with partial intrinsic efficacy and affinity for the receptor. Giving a partial agonist after a pure agonist will not increase receptor occupancy or decrease receptor activity, and thus will not affect drug A’s efficacy. The inverse agonist flumazenil can reverse all benzodiazepines.

      An inverse agonist is a drug that binds to the receptor but has the opposite pharmacological effect.

      A non-competitive antagonist is a drug that has affinity for a receptor but has different pharmacological effects and reduces the efficacy of an agonist for that receptor.

    • This question is part of the following fields:

      • Pharmacology
      47.9
      Seconds
  • Question 30 - A 240 volt alternating current (AC) socket from a wall is used to...

    Incorrect

    • A 240 volt alternating current (AC) socket from a wall is used to charge a direct current (DC) cardiac defibrillator.

      Name the electrical component that converts AC to DC.

      Your Answer:

      Correct Answer: Rectifier

      Explanation:

      There are two types of defibrillators
      AC defibrillator
      DC defibrillator

      AC defibrillator,
      consists of a step-up transformer with primary and secondary winding and two switches. Since secondary coil consists of more turns of wire than the primary coil, it induces larger voltage. A voltage value ranging between 250V to 750V is applied for AC external defibrillator. And used to enable the charging of a capacitor.

      DC defibrillator,
      consists of auto transformer T1 that acts as primary of the high voltage transformer T2. Is an iron core that transfers energy between 2 circuits by electromagnetic induction. Transformers are used to isolate circuits, change impedance and alter voltage output. transformers do not convert AC to DC.

      Diode rectifier composed of 4 diodes made of semiconductor material allows current to flow only in one direction. Alternating current (AC) passing through these diodes produces direct current (DC). Capacitor stores the charge in the form of an electrostatic field.

      Capacitor is used to convert the rectified AC voltage to produce DC voltage but capacitors do not directly convert AC to DC.

      Inductor induces a counter electromotive force(emf) that reduces the capacitor discharge value.

      In step-down transformer primary coils has more turns of wire than secondary coil, so induced voltage is smaller in the secondary coil.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
      0
      Seconds

SESSION STATS - PERFORMANCE PER SPECIALTY

Statistical Methods (0/5) 0%
Anatomy (1/6) 17%
Anaesthesia Related Apparatus (1/2) 50%
Pathophysiology (1/5) 20%
Physiology (0/1) 0%
Clinical Measurement (1/5) 20%
Basic Physics (0/2) 0%
Pharmacology (0/2) 0%
Physiology And Biochemistry (1/1) 100%
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